15x^2+62x+48=8x^2

Solution for 15x^2+62x+48=8x^2 equation:

15x^2+62x+48=8x^2

We move all terms to the left:

15x^2+62x+48-(8x^2)=0

determiningTheFunctionDomain
15x^2-8x^2+62x+48=0

We add all the numbers together, and all the variables

7x^2+62x+48=0

a = 7; b = 62; c = +48;
Δ = b2-4ac
Δ = 622-4·7·48
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-50}{2*7}=\frac{-112}{14}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+50}{2*7}=\frac{-12}{14}
=-6/7
$